Questions? Answers :)
Posted by mathbro on August 7, 2008
questions H.C.F
Q1 - Find the greatest number that will divide 185 and 300 leaving remainder 3 and 5 respectively.
A1 – Since dividing 185 the remainder left is 32, 182 will be exactly divisible by that number.
Similarly 300-6 = 294 will be exactly divisible by the number.
So the required H.C.F of 182 and 294 is 2 * 7 = 14
Q2 – Find the H.C.F of (2x^2 – x -1) and (4x^2 + 8x + 3)
Try this one…..
Ans is ( 2x + 1)
